16b^2-1=b

Solution for 16b^2-1=b equation:

16b^2-1=b

We move all terms to the left:

16b^2-1-(b)=0

We add all the numbers together, and all the variables

16b^2-1b-1=0

a = 16; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·16·(-1)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{65}}{2*16}=\frac{1-\sqrt{65}}{32}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{65}}{2*16}=\frac{1+\sqrt{65}}{32}
$